3(b+1)=4b-2(-3)

Solution for 3(b+1)=4b-2(-3) equation:

Simplifying
3(b + 1) = 4b + -2(-3)

Reorder the terms:
3(1 + b) = 4b + -2(-3)
(1 * 3 + b * 3) = 4b + -2(-3)
(3 + 3b) = 4b + -2(-3)

Multiply -2 * -3
3 + 3b = 4b + 6

Reorder the terms:
3 + 3b = 6 + 4b

Solving
3 + 3b = 6 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
3 + 3b + -4b = 6 + 4b + -4b

Combine like terms: 3b + -4b = -1b
3 + -1b = 6 + 4b + -4b

Combine like terms: 4b + -4b = 0
3 + -1b = 6 + 0
3 + -1b = 6

Add '-3' to each side of the equation.
3 + -3 + -1b = 6 + -3

Combine like terms: 3 + -3 = 0
0 + -1b = 6 + -3
-1b = 6 + -3

Combine like terms: 6 + -3 = 3
-1b = 3

Divide each side by '-1'.
b = -3

Simplifying
b = -3