3(b+1)=4b-2(b-3)

Solution for 3(b+1)=4b-2(b-3) equation:

Simplifying
3(b + 1) = 4b + -2(b + -3)

Reorder the terms:
3(1 + b) = 4b + -2(b + -3)
(1 * 3 + b * 3) = 4b + -2(b + -3)
(3 + 3b) = 4b + -2(b + -3)

Reorder the terms:
3 + 3b = 4b + -2(-3 + b)
3 + 3b = 4b + (-3 * -2 + b * -2)
3 + 3b = 4b + (6 + -2b)

Reorder the terms:
3 + 3b = 6 + 4b + -2b

Combine like terms: 4b + -2b = 2b
3 + 3b = 6 + 2b

Solving
3 + 3b = 6 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
3 + 3b + -2b = 6 + 2b + -2b

Combine like terms: 3b + -2b = 1b
3 + 1b = 6 + 2b + -2b

Combine like terms: 2b + -2b = 0
3 + 1b = 6 + 0
3 + 1b = 6

Add '-3' to each side of the equation.
3 + -3 + 1b = 6 + -3

Combine like terms: 3 + -3 = 0
0 + 1b = 6 + -3
1b = 6 + -3

Combine like terms: 6 + -3 = 3
1b = 3

Divide each side by '1'.
b = 3

Simplifying
b = 3