3(b+1)=5(b-5)

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Solution for 3(b+1)=5(b-5) equation:


Simplifying
3(b + 1) = 5(b + -5)

Reorder the terms:
3(1 + b) = 5(b + -5)
(1 * 3 + b * 3) = 5(b + -5)
(3 + 3b) = 5(b + -5)

Reorder the terms:
3 + 3b = 5(-5 + b)
3 + 3b = (-5 * 5 + b * 5)
3 + 3b = (-25 + 5b)

Solving
3 + 3b = -25 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
3 + 3b + -5b = -25 + 5b + -5b

Combine like terms: 3b + -5b = -2b
3 + -2b = -25 + 5b + -5b

Combine like terms: 5b + -5b = 0
3 + -2b = -25 + 0
3 + -2b = -25

Add '-3' to each side of the equation.
3 + -3 + -2b = -25 + -3

Combine like terms: 3 + -3 = 0
0 + -2b = -25 + -3
-2b = -25 + -3

Combine like terms: -25 + -3 = -28
-2b = -28

Divide each side by '-2'.
b = 14

Simplifying
b = 14

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