3(b+11)=27

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Solution for 3(b+11)=27 equation: 



3(b+11)=27

We move all terms to the left:

3(b+11)-(27)=0

We multiply parentheses

3b+33-27=0

We add all the numbers together, and all the variables

3b+6=0

We move all terms containing b to the left, all other terms to the right

3b=-6

b=-6/3

b=-2

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