3(b+12)=15

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Solution for 3(b+12)=15 equation: 



3(b+12)=15

We move all terms to the left:

3(b+12)-(15)=0

We multiply parentheses

3b+36-15=0

We add all the numbers together, and all the variables

3b+21=0

We move all terms containing b to the left, all other terms to the right

3b=-21

b=-21/3

b=-7

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