3(b+12)=72

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Solution for 3(b+12)=72 equation:



3(b+12)=72
We move all terms to the left:
3(b+12)-(72)=0
We multiply parentheses
3b+36-72=0
We add all the numbers together, and all the variables
3b-36=0
We move all terms containing b to the left, all other terms to the right
3b=36
b=36/3
b=12

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