3(b+15)=99

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Solution for 3(b+15)=99 equation: 



3(b+15)=99

We move all terms to the left:

3(b+15)-(99)=0

We multiply parentheses

3b+45-99=0

We add all the numbers together, and all the variables

3b-54=0

We move all terms containing b to the left, all other terms to the right

3b=54

b=54/3

b=18

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