3(b+2)+2(b-3)=5

Solution for 3(b+2)+2(b-3)=5 equation:

Simplifying
3(b + 2) + 2(b + -3) = 5

Reorder the terms:
3(2 + b) + 2(b + -3) = 5
(2 * 3 + b * 3) + 2(b + -3) = 5
(6 + 3b) + 2(b + -3) = 5

Reorder the terms:
6 + 3b + 2(-3 + b) = 5
6 + 3b + (-3 * 2 + b * 2) = 5
6 + 3b + (-6 + 2b) = 5

Reorder the terms:
6 + -6 + 3b + 2b = 5

Combine like terms: 6 + -6 = 0
0 + 3b + 2b = 5
3b + 2b = 5

Combine like terms: 3b + 2b = 5b
5b = 5

Solving
5b = 5

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Divide each side by '5'.
b = 1

Simplifying
b = 1