3(b+2)+3=18

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Solution for 3(b+2)+3=18 equation: 



3(b+2)+3=18

We move all terms to the left:

3(b+2)+3-(18)=0

We add all the numbers together, and all the variables

3(b+2)-15=0

We multiply parentheses

3b+6-15=0

We add all the numbers together, and all the variables

3b-9=0

We move all terms containing b to the left, all other terms to the right

3b=9

b=9/3

b=3

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