3(b+2)+4(b-3)=-20

Solution for 3(b+2)+4(b-3)=-20 equation:

Simplifying
3(b + 2) + 4(b + -3) = -20

Reorder the terms:
3(2 + b) + 4(b + -3) = -20
(2 * 3 + b * 3) + 4(b + -3) = -20
(6 + 3b) + 4(b + -3) = -20

Reorder the terms:
6 + 3b + 4(-3 + b) = -20
6 + 3b + (-3 * 4 + b * 4) = -20
6 + 3b + (-12 + 4b) = -20

Reorder the terms:
6 + -12 + 3b + 4b = -20

Combine like terms: 6 + -12 = -6
-6 + 3b + 4b = -20

Combine like terms: 3b + 4b = 7b
-6 + 7b = -20

Solving
-6 + 7b = -20

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 7b = -20 + 6

Combine like terms: -6 + 6 = 0
0 + 7b = -20 + 6
7b = -20 + 6

Combine like terms: -20 + 6 = -14
7b = -14

Divide each side by '7'.
b = -2

Simplifying
b = -2