3(b+2)+b=3(b-2)-2

Solution for 3(b+2)+b=3(b-2)-2 equation:

Simplifying
3(b + 2) + b = 3(b + -2) + -2

Reorder the terms:
3(2 + b) + b = 3(b + -2) + -2
(2 * 3 + b * 3) + b = 3(b + -2) + -2
(6 + 3b) + b = 3(b + -2) + -2

Combine like terms: 3b + b = 4b
6 + 4b = 3(b + -2) + -2

Reorder the terms:
6 + 4b = 3(-2 + b) + -2
6 + 4b = (-2 * 3 + b * 3) + -2
6 + 4b = (-6 + 3b) + -2

Reorder the terms:
6 + 4b = -6 + -2 + 3b

Combine like terms: -6 + -2 = -8
6 + 4b = -8 + 3b

Solving
6 + 4b = -8 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
6 + 4b + -3b = -8 + 3b + -3b

Combine like terms: 4b + -3b = 1b
6 + 1b = -8 + 3b + -3b

Combine like terms: 3b + -3b = 0
6 + 1b = -8 + 0
6 + 1b = -8

Add '-6' to each side of the equation.
6 + -6 + 1b = -8 + -6

Combine like terms: 6 + -6 = 0
0 + 1b = -8 + -6
1b = -8 + -6

Combine like terms: -8 + -6 = -14
1b = -14

Divide each side by '1'.
b = -14

Simplifying
b = -14