3(b+2)-(b-1)=0

Solution for 3(b+2)-(b-1)=0 equation:

Simplifying
3(b + 2) + -1(b + -1) = 0

Reorder the terms:
3(2 + b) + -1(b + -1) = 0
(2 * 3 + b * 3) + -1(b + -1) = 0
(6 + 3b) + -1(b + -1) = 0

Reorder the terms:
6 + 3b + -1(-1 + b) = 0
6 + 3b + (-1 * -1 + b * -1) = 0
6 + 3b + (1 + -1b) = 0

Reorder the terms:
6 + 1 + 3b + -1b = 0

Combine like terms: 6 + 1 = 7
7 + 3b + -1b = 0

Combine like terms: 3b + -1b = 2b
7 + 2b = 0

Solving
7 + 2b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 2b = 0 + -7

Combine like terms: 7 + -7 = 0
0 + 2b = 0 + -7
2b = 0 + -7

Combine like terms: 0 + -7 = -7
2b = -7

Divide each side by '2'.
b = -3.5

Simplifying
b = -3.5