3(b+2)-(b-4)=0

Solution for 3(b+2)-(b-4)=0 equation:

Simplifying
3(b + 2) + -1(b + -4) = 0

Reorder the terms:
3(2 + b) + -1(b + -4) = 0
(2 * 3 + b * 3) + -1(b + -4) = 0
(6 + 3b) + -1(b + -4) = 0

Reorder the terms:
6 + 3b + -1(-4 + b) = 0
6 + 3b + (-4 * -1 + b * -1) = 0
6 + 3b + (4 + -1b) = 0

Reorder the terms:
6 + 4 + 3b + -1b = 0

Combine like terms: 6 + 4 = 10
10 + 3b + -1b = 0

Combine like terms: 3b + -1b = 2b
10 + 2b = 0

Solving
10 + 2b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 2b = 0 + -10

Combine like terms: 10 + -10 = 0
0 + 2b = 0 + -10
2b = 0 + -10

Combine like terms: 0 + -10 = -10
2b = -10

Divide each side by '2'.
b = -5

Simplifying
b = -5