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3(b+2)-7=2b-5+b
We move all terms to the left:
3(b+2)-7-(2b-5+b)=0
We add all the numbers together, and all the variables
3(b+2)-(3b-5)-7=0
We multiply parentheses
3b-(3b-5)+6-7=0
We get rid of parentheses
3b-3b+5+6-7=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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