3(b+2)-b=2b+6

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Solution for 3(b+2)-b=2b+6 equation:


Simplifying
3(b + 2) + -1b = 2b + 6

Reorder the terms:
3(2 + b) + -1b = 2b + 6
(2 * 3 + b * 3) + -1b = 2b + 6
(6 + 3b) + -1b = 2b + 6

Combine like terms: 3b + -1b = 2b
6 + 2b = 2b + 6

Reorder the terms:
6 + 2b = 6 + 2b

Add '-6' to each side of the equation.
6 + -6 + 2b = 6 + -6 + 2b

Combine like terms: 6 + -6 = 0
0 + 2b = 6 + -6 + 2b
2b = 6 + -6 + 2b

Combine like terms: 6 + -6 = 0
2b = 0 + 2b
2b = 2b

Add '-2b' to each side of the equation.
2b + -2b = 2b + -2b

Combine like terms: 2b + -2b = 0
0 = 2b + -2b

Combine like terms: 2b + -2b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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