3(b+2)/4=(4b-16)/8

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Solution for 3(b+2)/4=(4b-16)/8 equation: 


b in (-oo:+oo)

(3*(b+2))/4 = (4*b-16)/8 // - (4*b-16)/8

(3*(b+2))/4-((4*b-16)/8) = 0

(3*(b+2))/4+(-1*(4*b-16))/8 = 0

(3*8*(b+2))/(4*8)+(-1*4*(4*b-16))/(4*8) = 0

3*8*(b+2)-1*4*(4*b-16) = 0

8*b+112 = 0

(8*b+112)/(4*8) = 0

(8*b+112)/(4*8) = 0 // * 4*8

8*b+112 = 0

8*b+112 = 0 // - 112

8*b = -112 // : 8

b = -112/8

b = -14

b = -14

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