3(b+2)=-5(b-2)

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Solution for 3(b+2)=-5(b-2) equation: 



3(b+2)=-5(b-2)

We move all terms to the left:

3(b+2)-(-5(b-2))=0

We multiply parentheses

3b-(-5(b-2))+6=0



We calculate terms in parentheses: -(-5(b-2)), so:

-5(b-2)

We multiply parentheses

-5b+10

Back to the equation:

-(-5b+10)



We get rid of parentheses

3b+5b-10+6=0

We add all the numbers together, and all the variables

8b-4=0

We move all terms containing b to the left, all other terms to the right

8b=4

b=4/8

b=1/2

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