3(b+2)=2(c+3)

Solution for 3(b+2)=2(c+3) equation:

Simplifying
3(b + 2) = 2(c + 3)

Reorder the terms:
3(2 + b) = 2(c + 3)
(2 * 3 + b * 3) = 2(c + 3)
(6 + 3b) = 2(c + 3)

Reorder the terms:
6 + 3b = 2(3 + c)
6 + 3b = (3 * 2 + c * 2)
6 + 3b = (6 + 2c)

Add '-6' to each side of the equation.
6 + -6 + 3b = 6 + -6 + 2c

Combine like terms: 6 + -6 = 0
0 + 3b = 6 + -6 + 2c
3b = 6 + -6 + 2c

Combine like terms: 6 + -6 = 0
3b = 0 + 2c
3b = 2c

Solving
3b = 2c

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Divide each side by '3'.
b = 0.6666666667c

Simplifying
b = 0.6666666667c