3(b+2)=3(b-2)

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Solution for 3(b+2)=3(b-2) equation:


Simplifying
3(b + 2) = 3(b + -2)

Reorder the terms:
3(2 + b) = 3(b + -2)
(2 * 3 + b * 3) = 3(b + -2)
(6 + 3b) = 3(b + -2)

Reorder the terms:
6 + 3b = 3(-2 + b)
6 + 3b = (-2 * 3 + b * 3)
6 + 3b = (-6 + 3b)

Add '-3b' to each side of the equation.
6 + 3b + -3b = -6 + 3b + -3b

Combine like terms: 3b + -3b = 0
6 + 0 = -6 + 3b + -3b
6 = -6 + 3b + -3b

Combine like terms: 3b + -3b = 0
6 = -6 + 0
6 = -6

Solving
6 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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