3(b+2)=3b+6

Solution for 3(b+2)=3b+6 equation:

Simplifying
3(b + 2) = 3b + 6

Reorder the terms:
3(2 + b) = 3b + 6
(2 * 3 + b * 3) = 3b + 6
(6 + 3b) = 3b + 6

Reorder the terms:
6 + 3b = 6 + 3b

Add '-6' to each side of the equation.
6 + -6 + 3b = 6 + -6 + 3b

Combine like terms: 6 + -6 = 0
0 + 3b = 6 + -6 + 3b
3b = 6 + -6 + 3b

Combine like terms: 6 + -6 = 0
3b = 0 + 3b
3b = 3b

Add '-3b' to each side of the equation.
3b + -3b = 3b + -3b

Combine like terms: 3b + -3b = 0
0 = 3b + -3b

Combine like terms: 3b + -3b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.