3(b+2)=6(b-2)

Solution for 3(b+2)=6(b-2) equation:

Simplifying
3(b + 2) = 6(b + -2)

Reorder the terms:
3(2 + b) = 6(b + -2)
(2 * 3 + b * 3) = 6(b + -2)
(6 + 3b) = 6(b + -2)

Reorder the terms:
6 + 3b = 6(-2 + b)
6 + 3b = (-2 * 6 + b * 6)
6 + 3b = (-12 + 6b)

Solving
6 + 3b = -12 + 6b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-6b' to each side of the equation.
6 + 3b + -6b = -12 + 6b + -6b

Combine like terms: 3b + -6b = -3b
6 + -3b = -12 + 6b + -6b

Combine like terms: 6b + -6b = 0
6 + -3b = -12 + 0
6 + -3b = -12

Add '-6' to each side of the equation.
6 + -6 + -3b = -12 + -6

Combine like terms: 6 + -6 = 0
0 + -3b = -12 + -6
-3b = -12 + -6

Combine like terms: -12 + -6 = -18
-3b = -18

Divide each side by '-3'.
b = 6

Simplifying
b = 6