3(b+2)=b+2b+3

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Solution for 3(b+2)=b+2b+3 equation: 



3(b+2)=b+2b+3

We move all terms to the left:

3(b+2)-(b+2b+3)=0

We add all the numbers together, and all the variables

3(b+2)-(3b+3)=0

We multiply parentheses

3b-(3b+3)+6=0

We get rid of parentheses

3b-3b-3+6=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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