3(b+3)+4b+8=4(b+8)

Solution for 3(b+3)+4b+8=4(b+8) equation:

Simplifying
3(b + 3) + 4b + 8 = 4(b + 8)

Reorder the terms:
3(3 + b) + 4b + 8 = 4(b + 8)
(3 * 3 + b * 3) + 4b + 8 = 4(b + 8)
(9 + 3b) + 4b + 8 = 4(b + 8)

Reorder the terms:
9 + 8 + 3b + 4b = 4(b + 8)

Combine like terms: 9 + 8 = 17
17 + 3b + 4b = 4(b + 8)

Combine like terms: 3b + 4b = 7b
17 + 7b = 4(b + 8)

Reorder the terms:
17 + 7b = 4(8 + b)
17 + 7b = (8 * 4 + b * 4)
17 + 7b = (32 + 4b)

Solving
17 + 7b = 32 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
17 + 7b + -4b = 32 + 4b + -4b

Combine like terms: 7b + -4b = 3b
17 + 3b = 32 + 4b + -4b

Combine like terms: 4b + -4b = 0
17 + 3b = 32 + 0
17 + 3b = 32

Add '-17' to each side of the equation.
17 + -17 + 3b = 32 + -17

Combine like terms: 17 + -17 = 0
0 + 3b = 32 + -17
3b = 32 + -17

Combine like terms: 32 + -17 = 15
3b = 15

Divide each side by '3'.
b = 5

Simplifying
b = 5