3(b+3)+b=3(b-4)-1

Solution for 3(b+3)+b=3(b-4)-1 equation:

Simplifying
3(b + 3) + b = 3(b + -4) + -1

Reorder the terms:
3(3 + b) + b = 3(b + -4) + -1
(3 * 3 + b * 3) + b = 3(b + -4) + -1
(9 + 3b) + b = 3(b + -4) + -1

Combine like terms: 3b + b = 4b
9 + 4b = 3(b + -4) + -1

Reorder the terms:
9 + 4b = 3(-4 + b) + -1
9 + 4b = (-4 * 3 + b * 3) + -1
9 + 4b = (-12 + 3b) + -1

Reorder the terms:
9 + 4b = -12 + -1 + 3b

Combine like terms: -12 + -1 = -13
9 + 4b = -13 + 3b

Solving
9 + 4b = -13 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
9 + 4b + -3b = -13 + 3b + -3b

Combine like terms: 4b + -3b = 1b
9 + 1b = -13 + 3b + -3b

Combine like terms: 3b + -3b = 0
9 + 1b = -13 + 0
9 + 1b = -13

Add '-9' to each side of the equation.
9 + -9 + 1b = -13 + -9

Combine like terms: 9 + -9 = 0
0 + 1b = -13 + -9
1b = -13 + -9

Combine like terms: -13 + -9 = -22
1b = -22

Divide each side by '1'.
b = -22

Simplifying
b = -22