3(b+3)-2b=11b-11

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Solution for 3(b+3)-2b=11b-11 equation: 



3(b+3)-2b=11b-11

We move all terms to the left:

3(b+3)-2b-(11b-11)=0

We add all the numbers together, and all the variables

-2b+3(b+3)-(11b-11)=0

We multiply parentheses

-2b+3b-(11b-11)+9=0

We get rid of parentheses

-2b+3b-11b+11+9=0

We add all the numbers together, and all the variables

-10b+20=0

We move all terms containing b to the left, all other terms to the right

-10b=-20

b=-20/-10

b=+2

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