3(b+3)-4(-2+b)=21

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Solution for 3(b+3)-4(-2+b)=21 equation: 



3(b+3)-4(-2+b)=21

We move all terms to the left:

3(b+3)-4(-2+b)-(21)=0

We add all the numbers together, and all the variables

3(b+3)-4(b-2)-21=0

We multiply parentheses

3b-4b+9+8-21=0

We add all the numbers together, and all the variables

-1b-4=0

We move all terms containing b to the left, all other terms to the right

-b=4

b=4/-1

b=-4

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