3(b+3)-4-(-2+b)=19

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Solution for 3(b+3)-4-(-2+b)=19 equation: 



3(b+3)-4-(-2+b)=19

We move all terms to the left:

3(b+3)-4-(-2+b)-(19)=0

We add all the numbers together, and all the variables

3(b+3)-(b-2)-4-19=0

We add all the numbers together, and all the variables

3(b+3)-(b-2)-23=0

We multiply parentheses

3b-(b-2)+9-23=0

We get rid of parentheses

3b-b+2+9-23=0

We add all the numbers together, and all the variables

2b-12=0

We move all terms containing b to the left, all other terms to the right

2b=12

b=12/2

b=6

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