3(b+3)-4=32

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Solution for 3(b+3)-4=32 equation: 



3(b+3)-4=32

We move all terms to the left:

3(b+3)-4-(32)=0

We add all the numbers together, and all the variables

3(b+3)-36=0

We multiply parentheses

3b+9-36=0

We add all the numbers together, and all the variables

3b-27=0

We move all terms containing b to the left, all other terms to the right

3b=27

b=27/3

b=9

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