3(b+3)=-(3b-3)

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Solution for 3(b+3)=-(3b-3) equation: 



3(b+3)=-(3b-3)

We move all terms to the left:

3(b+3)-(-(3b-3))=0

We multiply parentheses

3b-(-(3b-3))+9=0



We calculate terms in parentheses: -(-(3b-3)), so:

-(3b-3)

We get rid of parentheses

-3b+3

Back to the equation:

-(-3b+3)



We get rid of parentheses

3b+3b-3+9=0

We add all the numbers together, and all the variables

6b+6=0

We move all terms containing b to the left, all other terms to the right

6b=-6

b=-6/6

b=-1

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