3(b+4)+1=b+25

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Solution for 3(b+4)+1=b+25 equation: 



3(b+4)+1=b+25

We move all terms to the left:

3(b+4)+1-(b+25)=0

We multiply parentheses

3b-(b+25)+12+1=0

We get rid of parentheses

3b-b-25+12+1=0

We add all the numbers together, and all the variables

2b-12=0

We move all terms containing b to the left, all other terms to the right

2b=12

b=12/2

b=6

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