3(b+4)+b=3(b-3)-2

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Solution for 3(b+4)+b=3(b-3)-2 equation:


Simplifying
3(b + 4) + b = 3(b + -3) + -2

Reorder the terms:
3(4 + b) + b = 3(b + -3) + -2
(4 * 3 + b * 3) + b = 3(b + -3) + -2
(12 + 3b) + b = 3(b + -3) + -2

Combine like terms: 3b + b = 4b
12 + 4b = 3(b + -3) + -2

Reorder the terms:
12 + 4b = 3(-3 + b) + -2
12 + 4b = (-3 * 3 + b * 3) + -2
12 + 4b = (-9 + 3b) + -2

Reorder the terms:
12 + 4b = -9 + -2 + 3b

Combine like terms: -9 + -2 = -11
12 + 4b = -11 + 3b

Solving
12 + 4b = -11 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
12 + 4b + -3b = -11 + 3b + -3b

Combine like terms: 4b + -3b = 1b
12 + 1b = -11 + 3b + -3b

Combine like terms: 3b + -3b = 0
12 + 1b = -11 + 0
12 + 1b = -11

Add '-12' to each side of the equation.
12 + -12 + 1b = -11 + -12

Combine like terms: 12 + -12 = 0
0 + 1b = -11 + -12
1b = -11 + -12

Combine like terms: -11 + -12 = -23
1b = -23

Divide each side by '1'.
b = -23

Simplifying
b = -23

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