3(b+4)-(3+2b)=11

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Solution for 3(b+4)-(3+2b)=11 equation:


Simplifying
3(b + 4) + -1(3 + 2b) = 11

Reorder the terms:
3(4 + b) + -1(3 + 2b) = 11
(4 * 3 + b * 3) + -1(3 + 2b) = 11
(12 + 3b) + -1(3 + 2b) = 11
12 + 3b + (3 * -1 + 2b * -1) = 11
12 + 3b + (-3 + -2b) = 11

Reorder the terms:
12 + -3 + 3b + -2b = 11

Combine like terms: 12 + -3 = 9
9 + 3b + -2b = 11

Combine like terms: 3b + -2b = 1b
9 + 1b = 11

Solving
9 + 1b = 11

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 1b = 11 + -9

Combine like terms: 9 + -9 = 0
0 + 1b = 11 + -9
1b = 11 + -9

Combine like terms: 11 + -9 = 2
1b = 2

Divide each side by '1'.
b = 2

Simplifying
b = 2

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