3(b+4)-2=(b-1)

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Solution for 3(b+4)-2=(b-1) equation:


Simplifying
3(b + 4) + -2 = (b + -1)

Reorder the terms:
3(4 + b) + -2 = (b + -1)
(4 * 3 + b * 3) + -2 = (b + -1)
(12 + 3b) + -2 = (b + -1)

Reorder the terms:
12 + -2 + 3b = (b + -1)

Combine like terms: 12 + -2 = 10
10 + 3b = (b + -1)

Reorder the terms:
10 + 3b = (-1 + b)

Remove parenthesis around (-1 + b)
10 + 3b = -1 + b

Solving
10 + 3b = -1 + b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
10 + 3b + -1b = -1 + b + -1b

Combine like terms: 3b + -1b = 2b
10 + 2b = -1 + b + -1b

Combine like terms: b + -1b = 0
10 + 2b = -1 + 0
10 + 2b = -1

Add '-10' to each side of the equation.
10 + -10 + 2b = -1 + -10

Combine like terms: 10 + -10 = 0
0 + 2b = -1 + -10
2b = -1 + -10

Combine like terms: -1 + -10 = -11
2b = -11

Divide each side by '2'.
b = -5.5

Simplifying
b = -5.5

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