3(b+4)-2=2(b-1)

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Solution for 3(b+4)-2=2(b-1) equation:


Simplifying
3(b + 4) + -2 = 2(b + -1)

Reorder the terms:
3(4 + b) + -2 = 2(b + -1)
(4 * 3 + b * 3) + -2 = 2(b + -1)
(12 + 3b) + -2 = 2(b + -1)

Reorder the terms:
12 + -2 + 3b = 2(b + -1)

Combine like terms: 12 + -2 = 10
10 + 3b = 2(b + -1)

Reorder the terms:
10 + 3b = 2(-1 + b)
10 + 3b = (-1 * 2 + b * 2)
10 + 3b = (-2 + 2b)

Solving
10 + 3b = -2 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
10 + 3b + -2b = -2 + 2b + -2b

Combine like terms: 3b + -2b = 1b
10 + 1b = -2 + 2b + -2b

Combine like terms: 2b + -2b = 0
10 + 1b = -2 + 0
10 + 1b = -2

Add '-10' to each side of the equation.
10 + -10 + 1b = -2 + -10

Combine like terms: 10 + -10 = 0
0 + 1b = -2 + -10
1b = -2 + -10

Combine like terms: -2 + -10 = -12
1b = -12

Divide each side by '1'.
b = -12

Simplifying
b = -12

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