3(b+4)=(b+4)2

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Solution for 3(b+4)=(b+4)2 equation:


Simplifying
3(b + 4) = (b + 4) * 2

Reorder the terms:
3(4 + b) = (b + 4) * 2
(4 * 3 + b * 3) = (b + 4) * 2
(12 + 3b) = (b + 4) * 2

Reorder the terms:
12 + 3b = (4 + b) * 2

Reorder the terms for easier multiplication:
12 + 3b = 2(4 + b)
12 + 3b = (4 * 2 + b * 2)
12 + 3b = (8 + 2b)

Solving
12 + 3b = 8 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
12 + 3b + -2b = 8 + 2b + -2b

Combine like terms: 3b + -2b = 1b
12 + 1b = 8 + 2b + -2b

Combine like terms: 2b + -2b = 0
12 + 1b = 8 + 0
12 + 1b = 8

Add '-12' to each side of the equation.
12 + -12 + 1b = 8 + -12

Combine like terms: 12 + -12 = 0
0 + 1b = 8 + -12
1b = 8 + -12

Combine like terms: 8 + -12 = -4
1b = -4

Divide each side by '1'.
b = -4

Simplifying
b = -4

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