3(b+4)=2(b+6)

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Solution for 3(b+4)=2(b+6) equation: 



3(b+4)=2(b+6)

We move all terms to the left:

3(b+4)-(2(b+6))=0

We multiply parentheses

3b-(2(b+6))+12=0



We calculate terms in parentheses: -(2(b+6)), so:

2(b+6)

We multiply parentheses

2b+12

Back to the equation:

-(2b+12)



We get rid of parentheses

3b-2b-12+12=0

We add all the numbers together, and all the variables

b=0

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