3(b+4)=24-b

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Solution for 3(b+4)=24-b equation: 



3(b+4)=24-b

We move all terms to the left:

3(b+4)-(24-b)=0

We add all the numbers together, and all the variables

3(b+4)-(-1b+24)=0

We multiply parentheses

3b-(-1b+24)+12=0

We get rid of parentheses

3b+1b-24+12=0

We add all the numbers together, and all the variables

4b-12=0

We move all terms containing b to the left, all other terms to the right

4b=12

b=12/4

b=3

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