3(b+4)=2n+40

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Solution for 3(b+4)=2n+40 equation:


Simplifying
3(b + 4) = 2n + 40

Reorder the terms:
3(4 + b) = 2n + 40
(4 * 3 + b * 3) = 2n + 40
(12 + 3b) = 2n + 40

Reorder the terms:
12 + 3b = 40 + 2n

Solving
12 + 3b = 40 + 2n

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 3b = 40 + -12 + 2n

Combine like terms: 12 + -12 = 0
0 + 3b = 40 + -12 + 2n
3b = 40 + -12 + 2n

Combine like terms: 40 + -12 = 28
3b = 28 + 2n

Divide each side by '3'.
b = 9.333333333 + 0.6666666667n

Simplifying
b = 9.333333333 + 0.6666666667n

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