3(b+4)=5(b-2)

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Solution for 3(b+4)=5(b-2) equation:


Simplifying
3(b + 4) = 5(b + -2)

Reorder the terms:
3(4 + b) = 5(b + -2)
(4 * 3 + b * 3) = 5(b + -2)
(12 + 3b) = 5(b + -2)

Reorder the terms:
12 + 3b = 5(-2 + b)
12 + 3b = (-2 * 5 + b * 5)
12 + 3b = (-10 + 5b)

Solving
12 + 3b = -10 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
12 + 3b + -5b = -10 + 5b + -5b

Combine like terms: 3b + -5b = -2b
12 + -2b = -10 + 5b + -5b

Combine like terms: 5b + -5b = 0
12 + -2b = -10 + 0
12 + -2b = -10

Add '-12' to each side of the equation.
12 + -12 + -2b = -10 + -12

Combine like terms: 12 + -12 = 0
0 + -2b = -10 + -12
-2b = -10 + -12

Combine like terms: -10 + -12 = -22
-2b = -22

Divide each side by '-2'.
b = 11

Simplifying
b = 11

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