3(b+5)-5(b-1)=0

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Solution for 3(b+5)-5(b-1)=0 equation:


Simplifying
3(b + 5) + -5(b + -1) = 0

Reorder the terms:
3(5 + b) + -5(b + -1) = 0
(5 * 3 + b * 3) + -5(b + -1) = 0
(15 + 3b) + -5(b + -1) = 0

Reorder the terms:
15 + 3b + -5(-1 + b) = 0
15 + 3b + (-1 * -5 + b * -5) = 0
15 + 3b + (5 + -5b) = 0

Reorder the terms:
15 + 5 + 3b + -5b = 0

Combine like terms: 15 + 5 = 20
20 + 3b + -5b = 0

Combine like terms: 3b + -5b = -2b
20 + -2b = 0

Solving
20 + -2b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + -2b = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -2b = 0 + -20
-2b = 0 + -20

Combine like terms: 0 + -20 = -20
-2b = -20

Divide each side by '-2'.
b = 10

Simplifying
b = 10

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