3(b+5)/3=4(2b-5)/6

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Solution for 3(b+5)/3=4(2b-5)/6 equation: 



3(b+5)/3=4(2b-5)/6

We move all terms to the left:

3(b+5)/3-(4(2b-5)/6)=0

We calculate fractions


3b/()+(-(4(2b-5)*3)/()=0



We calculate terms in parentheses: +(-(4(2b-5)*3)/(), so:

-(4(2b-5)*3)/(

We multiply all the terms by the denominator


-(4(2b-5)*3)



We calculate terms in parentheses: -(4(2b-5)*3), so:

4(2b-5)*3

We multiply parentheses

24b-60

Back to the equation:

-(24b-60)



We get rid of parentheses

-24b+60

Back to the equation:

+(-24b+60)



We get rid of parentheses

3b/()-24b+60=0

We multiply all the terms by the denominator


3b-24b*()+60*()=0

We add all the numbers together, and all the variables

3b-24b*()=0

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