3(b+5)=2(b-5)+20

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Solution for 3(b+5)=2(b-5)+20 equation: 


Simplifying
3(b + 5) = 2(b + -5) + 20

Reorder the terms:
3(5 + b) = 2(b + -5) + 20
(5 * 3 + b * 3) = 2(b + -5) + 20
(15 + 3b) = 2(b + -5) + 20

Reorder the terms:
15 + 3b = 2(-5 + b) + 20
15 + 3b = (-5 * 2 + b * 2) + 20
15 + 3b = (-10 + 2b) + 20

Reorder the terms:
15 + 3b = -10 + 20 + 2b

Combine like terms: -10 + 20 = 10
15 + 3b = 10 + 2b

Solving
15 + 3b = 10 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
15 + 3b + -2b = 10 + 2b + -2b

Combine like terms: 3b + -2b = 1b
15 + 1b = 10 + 2b + -2b

Combine like terms: 2b + -2b = 0
15 + 1b = 10 + 0
15 + 1b = 10

Add '-15' to each side of the equation.
15 + -15 + 1b = 10 + -15

Combine like terms: 15 + -15 = 0
0 + 1b = 10 + -15
1b = 10 + -15

Combine like terms: 10 + -15 = -5
1b = -5

Divide each side by '1'.
b = -5

Simplifying
b = -5

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