3(b+5)=2(b-6)

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Solution for 3(b+5)=2(b-6) equation: 



3(b+5)=2(b-6)

We move all terms to the left:

3(b+5)-(2(b-6))=0

We multiply parentheses

3b-(2(b-6))+15=0



We calculate terms in parentheses: -(2(b-6)), so:

2(b-6)

We multiply parentheses

2b-12

Back to the equation:

-(2b-12)



We get rid of parentheses

3b-2b+12+15=0

We add all the numbers together, and all the variables

b+27=0

We move all terms containing b to the left, all other terms to the right

b=-27

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