3(b+5)=2(b-8)

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Solution for 3(b+5)=2(b-8) equation: 



3(b+5)=2(b-8)

We move all terms to the left:

3(b+5)-(2(b-8))=0

We multiply parentheses

3b-(2(b-8))+15=0



We calculate terms in parentheses: -(2(b-8)), so:

2(b-8)

We multiply parentheses

2b-16

Back to the equation:

-(2b-16)



We get rid of parentheses

3b-2b+16+15=0

We add all the numbers together, and all the variables

b+31=0

We move all terms containing b to the left, all other terms to the right

b=-31

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