3(b+5)=2(b-8)

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Solution for 3(b+5)=2(b-8) equation:



3(b+5)=2(b-8)
We move all terms to the left:
3(b+5)-(2(b-8))=0
We multiply parentheses
3b-(2(b-8))+15=0
We calculate terms in parentheses: -(2(b-8)), so:
2(b-8)
We multiply parentheses
2b-16
Back to the equation:
-(2b-16)
We get rid of parentheses
3b-2b+16+15=0
We add all the numbers together, and all the variables
b+31=0
We move all terms containing b to the left, all other terms to the right
b=-31

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