3(b+5)=27+b

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Solution for 3(b+5)=27+b equation:



3(b+5)=27+b
We move all terms to the left:
3(b+5)-(27+b)=0
We add all the numbers together, and all the variables
3(b+5)-(b+27)=0
We multiply parentheses
3b-(b+27)+15=0
We get rid of parentheses
3b-b-27+15=0
We add all the numbers together, and all the variables
2b-12=0
We move all terms containing b to the left, all other terms to the right
2b=12
b=12/2
b=6

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