3(b+5)=27+b

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Solution for 3(b+5)=27+b equation: 



3(b+5)=27+b

We move all terms to the left:

3(b+5)-(27+b)=0

We add all the numbers together, and all the variables

3(b+5)-(b+27)=0

We multiply parentheses

3b-(b+27)+15=0

We get rid of parentheses

3b-b-27+15=0

We add all the numbers together, and all the variables

2b-12=0

We move all terms containing b to the left, all other terms to the right

2b=12

b=12/2

b=6

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