3(b+5)=3(b-2)

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Solution for 3(b+5)=3(b-2) equation: 



3(b+5)=3(b-2)

We move all terms to the left:

3(b+5)-(3(b-2))=0

We multiply parentheses

3b-(3(b-2))+15=0



We calculate terms in parentheses: -(3(b-2)), so:

3(b-2)

We multiply parentheses

3b-6

Back to the equation:

-(3b-6)



We get rid of parentheses

3b-3b+6+15=0

We add all the numbers together, and all the variables

21!=0

There is no solution for this equation

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