3(b+5)=4(2b-2)

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Solution for 3(b+5)=4(2b-2) equation:



3(b+5)=4(2b-2)
We move all terms to the left:
3(b+5)-(4(2b-2))=0
We multiply parentheses
3b-(4(2b-2))+15=0
We calculate terms in parentheses: -(4(2b-2)), so:
4(2b-2)
We multiply parentheses
8b-8
Back to the equation:
-(8b-8)
We get rid of parentheses
3b-8b+8+15=0
We add all the numbers together, and all the variables
-5b+23=0
We move all terms containing b to the left, all other terms to the right
-5b=-23
b=-23/-5
b=4+3/5

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