3(b+5)=4(2b-5)=

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Solution for 3(b+5)=4(2b-5)= equation:



3(b+5)=4(2b-5)=
We move all terms to the left:
3(b+5)-(4(2b-5))=0
We multiply parentheses
3b-(4(2b-5))+15=0
We calculate terms in parentheses: -(4(2b-5)), so:
4(2b-5)
We multiply parentheses
8b-20
Back to the equation:
-(8b-20)
We get rid of parentheses
3b-8b+20+15=0
We add all the numbers together, and all the variables
-5b+35=0
We move all terms containing b to the left, all other terms to the right
-5b=-35
b=-35/-5
b=+7

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