3(b+5)=5(b-1)

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Solution for 3(b+5)=5(b-1) equation: 



3(b+5)=5(b-1)

We move all terms to the left:

3(b+5)-(5(b-1))=0

We multiply parentheses

3b-(5(b-1))+15=0



We calculate terms in parentheses: -(5(b-1)), so:

5(b-1)

We multiply parentheses

5b-5

Back to the equation:

-(5b-5)



We get rid of parentheses

3b-5b+5+15=0

We add all the numbers together, and all the variables

-2b+20=0

We move all terms containing b to the left, all other terms to the right

-2b=-20

b=-20/-2

b=+10

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