3(b+6)=-3(b-2)

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Solution for 3(b+6)=-3(b-2) equation: 



3(b+6)=-3(b-2)

We move all terms to the left:

3(b+6)-(-3(b-2))=0

We multiply parentheses

3b-(-3(b-2))+18=0



We calculate terms in parentheses: -(-3(b-2)), so:

-3(b-2)

We multiply parentheses

-3b+6

Back to the equation:

-(-3b+6)



We get rid of parentheses

3b+3b-6+18=0

We add all the numbers together, and all the variables

6b+12=0

We move all terms containing b to the left, all other terms to the right

6b=-12

b=-12/6

b=-2

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